Quantitative Aptitude: Quadratic Equations Set 4
Directions: In the following questions, two equations numbered are given in variables x and y. You have to solve both the equations and find out the relationship between x and y. Then give answer accordingly-
- I. 6x2 + 7x -3 = 0
II. y (10y – 1) = 2
A) x > y
B) x < y
C) x ≥ y
D) x ≤ y
E) x = y or relation cannot be established
- I. 4x2 + 3x – 27 = 0
II. 15y2 – 38y – 21 = 0
A) x > y
B) x < y
C) x ≥ y
D) x ≤ y
E) x = y or relation cannot be established
- I. 8x2 + 5x – 13 = 0
II. 2y2 + 23y + 63 = 0
A) x > y
B) x < y
C) x ≥ y
D) x ≤ y
E) x = y or relation cannot be established
- I. 4x2 + 19x + 21 = 0
II. 2y2 – 25y – 27 = 0
A) x > y
B) x < y
C) x ≥ y
D) x ≤ y
E) x = y or relation cannot be established
- I. x2 – 9x + 20 = 0
II. y2 – 11y + 30 = 0
A) x > y
B) x < y
C) x ≥ y
D) x ≤ y
E) x = y or relation cannot be established
- I. x2 – 7x + 12 = 0
II. y2 – 5y + 6 = 0
A) x > y
B) x < y
C) x ≥ y
D) x ≤ y
E) x = y or relation cannot be established
- I. x2 – 2x – 15 = 0
II. y2 + 22 = 122
A) x > y
B) x < y
C) x ≥ y
D) x ≤ y
E) x = y or relationship cannot be determined
- I. x2 + x – 30 = 0
II. y2 – 11y + 30 = 0
A) x > y
B) x < y
C) x ≥ y
D) x ≤ y
E) x = y or relation cannot be established
- I. 2 + 5x – 14 = 0
II. y2 + 24y + 128 = 0
A) x > y
B) x < y
C) x ≥ y
D) x ≤ y
E) x = y or relation cannot be established
- I. x2 – 6x – 91 = 0
II. y2 – 32y + 247 = 0
A) x > y
B) x < y
C) x ≥ y
D) x ≤ y
E) x = y or relationship cannot be determined