Quantitative Aptitude: Data Interpretation Set 5

Directions (1-5): Study the following table and answer the following:

1. Find the difference between the sales of products A and B in the year 2015.
   A) 154320
   B) 173580
   C) 143420
   D) 185280
   E) 165890
   
   View Answer

   Option B
   Explanation:
   Sales of A in 2015 = 2 lacs × 105/100 × 110/100 × 110/100 = 254100
   Sales of B in 2015 = 3 lacs × 108/100 × 110/100 × 120/100 = 427680
   So difference = 427680 – 254100 = 173580
2. Find the ratio of sales of product C in 2014 to the sales of product D in 2015.
   A) 875 : 654
   B) 825 : 763
   C) 962 : 744
   D) 796 : 733
   E) None of these
   
   View Answer

   Option B
   Explanation:
   Sales of C In 2014 = 3.6 lacs × 110/100 × 110/100
   Sales of D In 2015 = 3 lacs × 109/100 × 110/100 × 112/100
   So ratio = 3.6 lacs × 110/100 × 110/100 : 3 lacs × 109/100 × 110/100 × 112/100
3. What is the percentage increase in sales of all the four products in 2014 as compared to 2012?
   A) 14.22
   B) 15.67
   C) 20.97
   D) 18.35
   E) 19.19%
   
   View Answer

   Option E
   Explanation:
   Sales of A in 2014 = 2 lacs × 105/100 × 110/100 = 231000
   Sales of B in 2014 = 3 lacs × 108/100 × 110/100 = 356400
   Sales of C in 2014 = 3.6 lacs × 110/100 × 110/100 = 435600
   Sales of D in 2014 = 3 lacs × 109/100 × 110/100 = 359700
   So total sales in 2014 = 1382700
   Total sales in 2012 = 1160000
   So % increase = (1382700 – 1160000)/1160000 * 100 = 19.19%
   
4. Of all the products, which product showed the highest percentage increase in total sales at the of 2015 in four years?
   A) A
   B) B
   C) C
   D) D
   E) None of these
   
   View Answer

   Option B
   Explanation:
   Sales of A in 2015 = 2 lacs × 105/100 × 110/100 × 110/100 = 254100
   Sales of B in 2015 = 3 lacs × 108/100 × 110/100 × 120/100 = 427680
   Sales of C in 2015 = 3.6 lacs × 110/100 × 110/100 × 112/100 = 487872
   Sales of D in 2015 = 3 lacs × 109/100 × 110/100 × 112/100 = 402864
   So
   % increase in sales of product A = (254100-200000)/200000 * 100 = 27.05%
   % increase in sales of product B = (427680-300000)/300000 * 100 = 42.56%
   % increase in sales of product C = (487872-360000)/360000 * 100 = 35.52%
   % increase in sales of product D = (402864-300000)/300000 * 100 = 34.28%
   So maximum for B
5. If the ratio of defective to non-defective A products is 2 : 3 in 2012 while that of products C is 4 : 5 in same year, then what is the ratio of defective A products to non-defective B products in 2012?
   A) 1 : 4
   B) 4 : 7
   C) 3 : 7
   D) 2 : 5
   E) 2 : 7
   
   View Answer

   Option D
   Explanation:
   Number of defective A products in 2012 = 2/5 * 2,00,000 = 80,000
   Number of non-defective C products in 2012 = 5/9 * 3,60,000 = 2,00,000
   So required ratio = 80,000 : 2,00,000 = 2 : 5

Directions (6- 10): Study the following chart carefully and answer the questions that follow:
The chart shows the number of students in six 6 classes of 2 different schools ABC and XYZ.

6. What is the difference between the students of class II and IV in school ABC and the students of class I and V in school XYZ?
   A) 90
   B) 120
   C) 80
   D) 50
   E) 110
   
   View Answer

   Option C
   Explanation:
   II and IV in ABC = 280+620 = 900
   I and V in XYZ = 320+660 = 980
   
7. What is the ratio of number of students in classes I and IV in school ABC to number of students in classes II and VI in school XYZ?
   A) 23 : 56
   B) 45 : 59
   C) 43 : 55
   D) 25 : 41
   E) None of these
   
   View Answer

   Option C
   Explanation:
   24+62 : 36+74
   86 : 110
   43: 55
   
8. Students in school ABC are approximately what percent lesser than students in school XYZ?
   A) 15%
   B) 27%
   C) 33%
   D) 12%
   E) 22%
   
   View Answer

   Option E
   Explanation:
   In ABC = 2280
   In XYZ = 2920
   Required % = (2920-2280)/2920 * 100
   
9. If from school ABC, 5% and 10% of students of classes IV and I respectively gets shifted to same respective classes in school XYZ, then find the average number of students in classes I and IV in school XYZ.
   A) 429
   B) 553
   C) 467
   D) 429
   E) 534
   
   View Answer

   Option C
   Explanation:
   From D = 5/100 * 620 = 31
   From A = 10/100 * 240 = 24
   So now in A and D in XYZ = 320+24 + 560+31 = 935
   So average = 935/2 = 467.5
   
10. Students in class V in school ABC is what percent of the number of students in classes II and III together in school XYZ?
    A) 64.78%
    B) 68.75%
    C) 75.75%
    D) 99.35%
    E) 102.55%
    
    View Answer

    Option B
    Explanation:
    440/(360+280) * 100