Quantitative Aptitude: Problems on Ages Set 3

Problems on Ages Bank PO, Insurance, SSC and other Exams with tricks

1. The present age of Sumit is 1/8^th of his father. After 4 years, the father’s age will be twice the age of Raman. If Raman celebrated his 6^th birthday eight years ago, what is Sumit’s present age?
   A) 4
   B) 6
   C) 5
   D) 8
   E) None of these
   
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    Option A
   Solution:
   Present ratio Sumit : Father is 1 : 8……………. (1)
   4 years after, Father : Raman is 2 : 1………………..(2)
   Raman’s 6^th birthday was 8 years ago, so after 4 years he will be 18 years old
   Put in equation (2), Raman = 18, Father = 36
   So present age of father = 32
   So of Sumit is 32/8 = 4 years
2. Sita’s present age is five times of her daughter’s age and 1/3^rd of her father’s age. If the average age of all the three is 28 years, then find the difference between Sita’s daughter’s age and her father’s age.
   A) 50
   B) 40
   C) 56
   D) 55
   E) 62
   
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    Option C
   Solution:
   Sita : Daughter = 5 : 1
   Sita : Father = 1: 3 or 5 : 15
   Total age of 3 = 1 + 5 + 15 = 21
   So average = 21/3 = 7
   7…….28
   1……..4
   Sita’s daughter = 4
   So her father’s = 60
   Difference = 56 years
3. Sheetal’s age at the time of her marriage was 4/5^th of her present age. If she married 6 years ago and now she has a son who is 1/10^th of her present age, then find the age of her son 5 years hence.
   A) 3
   B) 8
   C) 9
   D) 10
   E) 12
   
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    Option D
   Solution:
   4/5 * 6 = 24/30
   24 => at the time of marriage
   30 years => now
   Son = 1/10 of present age = 1/10 * 30 = 3 years
   5 years hence = 3+5 = 8 years
4. Ram is 6 years elder then his brother and 5 years younger than her sister Sheena. When Sheena was born, her father’s age was 24 and when Ram’s brother was born his mother’s age was 29. Find the difference between ages of Ram’s father and his mother.
   A) 10
   B) 8
   C) 6
   D) Cannot be determined
   E) None of these
   
   View Answer

    Option C
   Solution:
   Bother=x
   Ram=x+6
   Sheena=x+11
   Father=x+11+24=x+35
   Mother=x+29
   Difference=x+35 –(x+29)=6 years
   
5. When a couple was married, their average age was 22 years. When their first child was born, the average age of all the three became16 years. When their second child was born, the average of all 4 became 15 years. Find the average age of couple at the time when their second child was born.
   A) 20
   B) 28
   C) 30
   D) 32
   E) 25
   
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    Option B
   Solution:
   At the time of marriage total age of couple=44
   when 1^st child is born total age of three=16*3=48
   Difference=48-44=4 years (Child is of 0 years hence this is the sum of age incrase of couple)
   When second child is born sum of age=4*15=60 years
   => increase of 12 years after first child, means age of husband, wife and first child increased by 4 years each. SO increase in husband and wife total age = 8 years
   total increase =4+8=12
   total age=44+12=56; average=56/2=28 years
   
6. Five years ago, the ratio of ages of A and B was 5 : 3 and five years hence from now, the ratio will become 7 : 5. Find the average of their present ages.
   A) 15
   B) 18
   C) 21
   D) 25
   E) 24
   
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   Option D
   Solution:
   ———————A———–B
   5 years ago—–5————-3
   …………………—7————–5
   In both case increase of 2 years 7-5=2 and 5-3=2
   hence this increase of 2 years is for 10 years
   =>1=5
   hence A=5*5+5=30
   B=3*5+5=20
   Average=25
7. Four years ago, the ratio of ages of Vishal and Devansh was 3 : 5. Four years from now, the respective ratio will become 2 : 3. What is the ratio of age of Vishal 4 years ago and Devansh’s present age?
   A) 4 : 5
   B) 1 : 2
   C) 6 : 11
   D) 3 : 4
   E) 9 : 13
   
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    Option C
   Solution:
   —————————–V——————–D
   4 years ago ————–3———————-5    ——-(eq 1)
   4 years hence————2———————–3 ——- (eq 2)
   Difference of V= 3-2=1; Difference of D= 5-3=2
   to make this difference equal multiply eq 2, by 2 we get
   —————————–V——————–D
   4 years ago ————–3———————-5    ——-(eq 1)
   4 years hence————4———————–6 ——- (eq 2)
   difference = 1 in both case
   This is for 8 years =>1= 8 years
   V=3*8=24 (4 years ago)
   D=5*8=40 (4 years ago)
   ratio =24/44=6:11
    
8. The average age of 10 men increased by 1 when two men of age 25 and 27 years are replaced by 2 other men. Find the average age of new men.
   A) 31
   B) 30
   C) 26
   D) 33
   E) 28
   
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    Option A
   Solution:
   Sum of age of leaving person=52
   total increase of of age=10*1=10 years
   increased total age due to addition of two men=52+10=62; Avg=31
   
9. The average age of a group of 20 men is 22 years. If two men whose age are 24 and 31 years respectively join the group, the average age of new group increase or decrease by
   A) No increment , no decrement
   B) increase by 0.5 year
   C) decrease by 0.5 year
   D) increase by 1 year
   E) decrease by 1 year
   
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    Option B
   Solution:
   When 2 new people join if the sum of their age is 44 then the average will not change, but the sum of age of new people is 55 i.e increase of 11
   hence avg increases by 11/22=0.5 years.
   
10. The ratio of present age of Tiya and Piya is 3 : 5 and the ratio of ages of Tiya 5 years ago and Piya 5 years hence is 1 : 3. Find the present age of Piya.
    A) 10
    B) 25
    C) 15
    D) 30
    E) 31
    
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     Option B
    Solution:
    T/P=3/5 ——- (i)
    T-5/P+5 =1/3 ———- (ii)
    Solve and get
    T=15 years
    P= 25 years